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2×2 eigenvalues

Eigenvalues & eigenvectors

Japanese school year: University year 1

What you learn

Learn how to calculate the eigenvalues of a 2x2 matrix by solving its characteristic equation. An eigenvalue represents the scalar factor by which a nonzero vector is scaled under a linear transformation. Prior understanding of determinants and quadratic equation solving methods is required.

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Key points

This is the characteristic equation used to find eigenvalues λ\lambda of matrix AA. Setting this determinant to 0 ensures that non-zero eigenvectors exist.

det⁡(A−λI)=0\det(A - \lambda I) = 0

This quadratic equation lets you quickly find eigenvalues λ\lambda for a 2×22 \times 2 matrix. Just plug in the diagonal sum tr⁡(A)\operatorname{tr}(A) and determinant det⁡(A)\det(A), then solve for λ\lambda.

λ2−tr⁡(A)λ+det⁡(A)=0\lambda^2 - \operatorname{tr}(A)\lambda + \det(A) = 0

Use these relations to check if your calculated eigenvalues λ1\lambda_1 and λ2\lambda_2 are correct. Their sum equals the diagonal sum tr⁡(A)\operatorname{tr}(A), and their product equals det⁡(A)\det(A).

λ1+λ2=tr⁡(A),λ1λ2=det⁡(A)\lambda_1 + \lambda_2 = \operatorname{tr}(A), \quad \lambda_1 \lambda_2 = \det(A)

Choose a set to practice.