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Math Drills
Linear systems & matrices
Row reduction
Practice 1
Linear systems & matrices
Row reduction
1 / 5
Standard
Put the augmented matrix into reduced row echelon form.
rref
(
2
3
7
3
−
1
5
)
\operatorname{rref} \begin{pmatrix} 2 & 3 & 7 \\ 3 & -1 & 5 \end{pmatrix}
rref
(
2
3
3
−
1
7
5
)
1
(
1
0
1
0
1
2
)
\begin{pmatrix} 1 & 0 & 1 \\ 0 & 1 & 2 \end{pmatrix}
(
1
0
0
1
1
2
)
2
(
1
0
2
0
1
1
)
\begin{pmatrix} 1 & 0 & 2 \\ 0 & 1 & 1 \end{pmatrix}
(
1
0
0
1
2
1
)
3
(
1
0
2
0
1
−
1
)
\begin{pmatrix} 1 & 0 & 2 \\ 0 & 1 & -1 \end{pmatrix}
(
1
0
0
1
2
−
1
)
4
(
1
0
−
2
0
1
1
)
\begin{pmatrix} 1 & 0 & -2 \\ 0 & 1 & 1 \end{pmatrix}
(
1
0
0
1
−
2
1
)
Answer
