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Math Drills
Differentiation
Velocity & acceleration
Practice 1
Differentiation
Velocity & acceleration
1 / 5
Standard
Find the value when
t
=
3
t = 3
t
=
3
.
d
d
t
(
−
t
3
+
6
t
2
−
5
t
+
2
)
\frac{d}{dt}\left(-t^{3} + 6t^{2} - 5t + 2\right)
d
t
d
(
−
t
3
+
6
t
2
−
5
t
+
2
)
1
4
4
4
2
6
6
6
3
−
2
-2
−
2
4
14
14
14
Answer
